Suresh have “N” rectangles. A rectangle is Silver if the ratio of its sides is in between [1.6, 1.7], both inclusive. Your task is to find the number of silver rectangles.

Constraints:

1 <-N <-10^5

1 <- W, H <- 10^9

Input Format:

First line: Integer “N” denoting the number of rectangles Each of the “N” following lines:

Two integers W, H denoting the width and height of a rectangle

Output Format.

Print the output in a single line contains find the number of Silver rectangles.

Sample Input:

5

10 1

165 100

180 100

170 100

160 100

Sample Output:

3

Explanation:

There are three Silver rectangles: (165, 100), (170, 100), (160, 100)

#include<stdio.h> #include<math.h> int main() { float n,i,width,height; printf("Enter the N triangle: "); scanf("%f",&n); int count=0; printf("Enter the width and height of triangle:\n"); for(i=0;i<n;i++) { scanf("%f %f",&width,&height); if(width/height>=1.6 && width/height<=1.7) ++count; else if(height/width >=1.6 && height/width<=1.7) ++count; } printf("Total Silver rectangles are %d \n",count+1); return 0; }

**ScrShot**

**Input:**Enter the N triangle: 5

Enter the width and height of triangle:

10 1

165 100

180 100

170 100

160 100

**Output:**

Total Silver rectangles are 3

**Input:**Enter the N triangle: 3

Enter the width and height of triangle:

50 100

200 300

120 190

**Output:**

Total Silver rectangles are 1

**Input:**Enter the N triangle: 4

Enter the width and height of triangle:

250 600

300 210

150 180

100 200

**Output:**

Total Silver rectangles are 1