Simon has given N ratios in the form of A and B that is represented as A/B.

#include<iostream>
using namespace std;
double func(double arr[10][2],double r,int n)
{
  double ans = 0;
  for(int i = 0; i < n; i++)
  {
    ans+= arr[i][0]/(arr[i][1]+r);
  }
  return ans;
}
double maxi(double arr[10][2],int n)
{ double m=0;
  for(int i=0;i<n;i++)
  {
    if(m<arr[i][1]){m=arr[i][1];}
  }
  return m;
}
int main()
{
  int n,col;
  cout<<"Enter the value of N and col(2 respectively):  ";
  cin>>n>>col;
  double arr[10][2];  //col == 2
  cout<<"Enter the ratio in form A and B: ";
  for (int i = 0; i < n; i++)
  {
    cin>>arr[i][0]>>arr[i][1];
  }
  double hi=maxi(arr,n),lo=0.0,mid=0.0;
  double curr,k;
  cout<<"Enter  the K value: ";
  cin>>k;
  while(hi-lo>1e-7)
  {
    mid=(hi+lo)/2;
    curr=func(arr,mid,n);
    if(curr<k)
    {
      lo = mid + 1e-7;
    }
    else
    {
      hi = mid - 1e-7;
    }
  }
  printf("%.6f",lo);
  return 0;
}