Given binary array, find count of maximum number of consecutive 1’s present in the array.

**Input :** arr[] = {1, 1, 0, 0, 1, 0, 1, 0, 1, 1, 1, 1}
**Output :** 4
**Input :** arr[] = {0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1}
**Output :** 1

def maxibin(arr): temp=0 count=0 for i in range(len(arr)): if arr[i]==0 : count=0 else: count+=1 temp=max(count,temp) return temp Arry=list(map(int,input('arr[] : ').split(' '))) print(maxibin(Arry))

**Input_1:**

arr[ ] : 1 1 0 0 1 0 1 0 1 1 1 1

**Output:**

4

**Input_2:**

arr[ ] : 0 0 1 0 1 0 1 0 1 0 1**Output**

1

**Input_3:**

arr[ ] : 1 1 1 0 1 0 1 0 1 1 1 0**Output:**

3

**Input_4:**

arr[ ] : 1 1 1 0 1 1 0 1 1 1 1 0 1 1 1**Output:**

4

**Illustration of the Output:**

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