Find the start and end index of unsorted subarray such that sorting this subarray can sort all the array.

**Input:** [2,6,4,8,10,9,15]
**Output:** 1 5
*#Starting Index is ***1 **and Ending index is **5**

def shortsub(arr): N=len(arr) L,arr1 = [],arr[:] arr1.sort() for i in range(N): if(arr[i]!=arr1[i]): L.append(i) if bool(L): return [L[0],L[-1]] else: return 0 A=list(map(int,input("Array: ").split(" "))) L=shortsub(A) print(L[0],L[1]) if L!=0 else print(None)

**INPUT_1:**

Array: 2 6 4 8 10 9 15

**OUTPUT:**

1 5

**INPUT_2:**

Array: 1 2 3 4

**OUTPUT:**

None

**INPUT_3:**

Array: 1

**OUTPUT:**

None

**INPUT_4:**

Array: 10 12 20 30 25 40 32 31 35 50 60

**OUTPUT:**

3 8

**INPUT_5:**

Array: 0 1 15 25 6 7 30 40 50

**OUTPUT:**

2 5

**ILLUSTRATION**