Find the minimized sum of non-deleted elements of the array after the end of the game

Polycarp has an array consisting of n integers.

He wants to play a game with this array. The game consists of several moves. On the first move, he chooses any element and deletes it (after the first move the array contains n−1 elements).

For each of the next moves he chooses any element with the only restriction: its parity should differ from the parity of the element deleted on the previous move. In other words, he alternates parities (even-odd-even-odd-… or odd-even-odd-even-…) of the removed elements. Polycarp stops if he can’t make a move.

Formally:

1. If it is the first move, he chooses any element and deletes it;
2. If it is the second or any next move:
– if the last deleted element was odd, Polycarp chooses any even element and deletes it;
– if the last deleted element was even, Polycarp chooses an odd element and deletes it.
3. If after some move Polycarp cannot make a move, the game ends.

Polycarp’s goal is to minimize the sum of non-deleted elements of the array after the end of the game. If Polycarp can delete the whole array, then the sum of non-deleted elements is zero.
Help Polycarp find this value.

``````Input:
The first line of the input contains one integer n — the number of elements of a.
The second line of the input contains n integers a1,a2,…,an, where ai is the i-th element of a.

Output:
Print one integer — the minimum possible sum of non-deleted elements of the array after the end of the game.``````
```#include <stdio.h>
#include <stdlib.h>
int cmp(const void *a, const void *b){
return *(int*)a - *(int*)b;
}
int main(){
int o[2000], ol = 0, e[2000], el = 0, n, t;
scanf("%d", &n);
while(n--) {
scanf("%d", &t);
if(t % 2)
o[ol++] = t;
else
e[el++] = t;
}
qsort(o, ol, sizeof(int), cmp);
qsort(e, el, sizeof(int), cmp);
while(ol && el) {
ol--;
el--;
}
t = 0;
if(ol) {
ol--;
while(ol)
t += o[--ol];
} else if(el) {
el--;
while(el)
t += e[--el];}
printf("%d", t);
return 0;
}
```

INPUT_1:
5
2  1  1  1  1

OUTPUT:
2

INPUT_2:
5
1  1  1  1  1

OUTPUT:
4

ILLUSTRATION

Morae Q!